Unified Field Theory
Mathematical Solutions
by Ezekial Davis
by Ezekial Davis
The Mathematical Solutions for my Unified Field Theory solves for Time Intensity on Energy Strings. Knowing Time Intensity you can solve for Energy and the speed of Light.
Mathematical Solutions :
Basic solution for solving with in our dimensions :
(Pressure X Heat Intensity = Time Intensity)
Solution for solving in all Dimensions :
((Pressure X Heat Intensity) divided by Orbits per Cycle = Time Intensity)
Basic definitions for understanding the mathematical solutions :
Pressure - The distance energy strings have to travel to complete a cycle. The size of the orbits energy strings travels in its cycles.
Heat Intensity - The speed energy strings travel or orbit.
Time Intensity - The speed and distance energy strings take to complete a cycle. for energy strings to have time intensity it must orbit one or more time per cycle.
Cycle - A Unit of Time. A full cycle of orbits. is when an energy strings orbit or orbits take it back to the same point it started from.
Orbit - The point when an energy string spins a full 360 degree.
Axis - A Theoretical line that passes threw the two intersecting points of an energy strings Orbits. the north and south poles of the Electromagnetic field created by multiple orbit per cycle energy strings.
Mathematics in use :
Scales to solve must start at Theoretical Absolute Zero. I picked the (psi) Pounds per Squire Inch scale to solve for Pressure, and the (Btu) British Thermal Unit Scale to solve for Heat Intensity. When solving for heat intensity you must calculate in the Sensible and the Latent heat. Latent heat is found in the changes of state in matter, and does not change the temperature of the matter that is in the change of state.
Pressure : (psi) Pounds per Squire Inch, from its theoretical absolute zero.
Heat Intensity : (Btu) British Thermal Unit, sensible and latent heat, from its theoretical absolute zero.
Exampled problem: solve for 1 pound (16oz) of water, at sea level on a 24 degree F day (Day 1) and compare it to a 96 degree day (Day 2), and solve for 288 degrees (*Day 3).
*** Solve for pressure***
(Pressure at Sea Level is about 14.696 psi.)
(1 pound of water is about 27.68 cubic inches)
1. step one is to calculate the surface space of the 1 pound of water.
a. 27 cubic inches makes a 6 sided cube, with 9 square inches on each side, so (9 X 6 =54)
b. 27 cubic inches has about 54 square inches of surface space. from here i see that 54 is 200% of 27. since 1 pound is 27.68 cubic inches and not 27 i will add the .68 cubic inches as 1.36 square inches. totaling 55.36 square inches in a "cubic" pound of water.
2. step two calculate Psi on the surface space
a. 14.696 psi X 55.36 square inches, equals 813.57056 psi on 1 (cubic) pound of water at sea level.
***Solve for Heat Intensity***
(Btu is the amount of energy needed to raise 1 pound of water 1 degree Fahrenheit, sensible.)
(takes 144 Btu`s to change 1pd of ice to water(32F), and 970 Btu`s to change 1pd of water from water to vapor (212F))
(Absolute Zero is about -459.67F.) (*Boss Einstein Condensate is not a change in state)
1. step one, find how much Btu`s are in 1pd of water at 0 degrees F, should be 459.67 Btu`s.
2. step two, add 24 Btu`s to solve for the 1st Day, = 483.67 Btu`s in (Day1), add 32 degrees for the other two, 491.67 Btu`s.
3. add the 144 Btu`s for the change in state at 32F, = 635.67 Btu`s. add 64 Btu to solve for (Day2) = 699.67 Btu`s.
4. step four, (212 - 32 = 180), 180 Btu`s between state changes. 635.67 + 180 = 815.67 to get to boiling point plus 970 to change state, = 1785.67 Btu`s. to solve for 288F,( - 212 = 76), add 76 to our Btu`s, = 1861.67.
Solving:
1.(Day 1) 1pd of water at 24F, sea level.
a. pressure is 813.57056psi, rounded to 814
b. Btu`s is 483.67, rounded to 484
c. (psi/Btu) Time Intensity is 393,976.
2.(Day 2) 1pd of water at 96F, sea level.
a. pressure is same 814
b. Btu`s is 699.67, rounded to 700.
c. (psi/Btu) Time Intensity is 569,800
3.(*Day 3) 1 pd of water vapor at 288F, sea level.
a. pressure same, 814
b. Btu`s is 1861.67. rounded to 1862
c.(psi/Btu) Time Intensity is 1,515,668
What does this mean to you? well time intensity out side on a summer day of 96F is 144.6% faster then a winter day of 24F. that mean time is passing by faster 144.6% faster.
Mathematical Solutions :
Basic solution for solving with in our dimensions :
(Pressure X Heat Intensity = Time Intensity)
Solution for solving in all Dimensions :
((Pressure X Heat Intensity) divided by Orbits per Cycle = Time Intensity)
Basic definitions for understanding the mathematical solutions :
Pressure - The distance energy strings have to travel to complete a cycle. The size of the orbits energy strings travels in its cycles.
Heat Intensity - The speed energy strings travel or orbit.
Time Intensity - The speed and distance energy strings take to complete a cycle. for energy strings to have time intensity it must orbit one or more time per cycle.
Cycle - A Unit of Time. A full cycle of orbits. is when an energy strings orbit or orbits take it back to the same point it started from.
Orbit - The point when an energy string spins a full 360 degree.
Axis - A Theoretical line that passes threw the two intersecting points of an energy strings Orbits. the north and south poles of the Electromagnetic field created by multiple orbit per cycle energy strings.
Mathematics in use :
Scales to solve must start at Theoretical Absolute Zero. I picked the (psi) Pounds per Squire Inch scale to solve for Pressure, and the (Btu) British Thermal Unit Scale to solve for Heat Intensity. When solving for heat intensity you must calculate in the Sensible and the Latent heat. Latent heat is found in the changes of state in matter, and does not change the temperature of the matter that is in the change of state.
Pressure : (psi) Pounds per Squire Inch, from its theoretical absolute zero.
Heat Intensity : (Btu) British Thermal Unit, sensible and latent heat, from its theoretical absolute zero.
Exampled problem: solve for 1 pound (16oz) of water, at sea level on a 24 degree F day (Day 1) and compare it to a 96 degree day (Day 2), and solve for 288 degrees (*Day 3).
*** Solve for pressure***
(Pressure at Sea Level is about 14.696 psi.)
(1 pound of water is about 27.68 cubic inches)
1. step one is to calculate the surface space of the 1 pound of water.
a. 27 cubic inches makes a 6 sided cube, with 9 square inches on each side, so (9 X 6 =54)
b. 27 cubic inches has about 54 square inches of surface space. from here i see that 54 is 200% of 27. since 1 pound is 27.68 cubic inches and not 27 i will add the .68 cubic inches as 1.36 square inches. totaling 55.36 square inches in a "cubic" pound of water.
2. step two calculate Psi on the surface space
a. 14.696 psi X 55.36 square inches, equals 813.57056 psi on 1 (cubic) pound of water at sea level.
***Solve for Heat Intensity***
(Btu is the amount of energy needed to raise 1 pound of water 1 degree Fahrenheit, sensible.)
(takes 144 Btu`s to change 1pd of ice to water(32F), and 970 Btu`s to change 1pd of water from water to vapor (212F))
(Absolute Zero is about -459.67F.) (*Boss Einstein Condensate is not a change in state)
1. step one, find how much Btu`s are in 1pd of water at 0 degrees F, should be 459.67 Btu`s.
2. step two, add 24 Btu`s to solve for the 1st Day, = 483.67 Btu`s in (Day1), add 32 degrees for the other two, 491.67 Btu`s.
3. add the 144 Btu`s for the change in state at 32F, = 635.67 Btu`s. add 64 Btu to solve for (Day2) = 699.67 Btu`s.
4. step four, (212 - 32 = 180), 180 Btu`s between state changes. 635.67 + 180 = 815.67 to get to boiling point plus 970 to change state, = 1785.67 Btu`s. to solve for 288F,( - 212 = 76), add 76 to our Btu`s, = 1861.67.
Solving:
1.(Day 1) 1pd of water at 24F, sea level.
a. pressure is 813.57056psi, rounded to 814
b. Btu`s is 483.67, rounded to 484
c. (psi/Btu) Time Intensity is 393,976.
2.(Day 2) 1pd of water at 96F, sea level.
a. pressure is same 814
b. Btu`s is 699.67, rounded to 700.
c. (psi/Btu) Time Intensity is 569,800
3.(*Day 3) 1 pd of water vapor at 288F, sea level.
a. pressure same, 814
b. Btu`s is 1861.67. rounded to 1862
c.(psi/Btu) Time Intensity is 1,515,668
What does this mean to you? well time intensity out side on a summer day of 96F is 144.6% faster then a winter day of 24F. that mean time is passing by faster 144.6% faster.
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