Tuesday, August 14, 2012

The Last Math Solution, by Ezekial Davis

The Last Math Solution, by Ezekial Davis
   
Math to solve energy, time, speed of light, and the interaction between different Electromagnetic Fields and Alternating Energy.

1. Understanding the Math Solution,
    1. Pressure X Orbits per cycle = The length a strand travels to compete a unit of Time.
    2. Heat Intensity = The speed a strand travels
    3. Energy = The resistance of the Strand. It`s strength to change and power to resist, Heat Transfer to and from other strands.
    4. Orbits per cycle = The number of times a strand completes 360° turns in tell it reach its starting point.
    5. Cycle = A unit of Time. the point a strand repeats its path, crossing over its starting point.
   
2. Math Solution.
       
    1. ( Pressure X Orbits per cycle / Heat Intensity= Time Intensity ), or ( Length / speed = Time ).
        * a equal change in Heat intensity and pressure (as a %) changes the Energy Level, not the time Intensity.
    2. ( Pressure X Orbits per cycle X Heat Intensity = Energy ), or ( Length X Speed = Energy ).

3. Scales.
   
    A. Scales must solve from theoretical absolute zero.
    B. the use of the scales on a object will calculate for it`s mass in the solutions.
            * I`ll use BTU`s and Psi a in the example solution.
        1. Absolute zero, −459.67° on the Fahrenheit scale.
        2. British thermal unit, It is approximately the amount of energy needed to heat 1 pound (0.454 kg) of water, its a traditional unit of energy equal to about 1.055 K Joules.
            A. Sensible Heat as a solid 491.67 BTU`s, (-459.67° to 32°), (~ - 491.67)
            B. Latent Heat of Fusion for Ice which is 144 BTU`s, (32°change in state), (491.67 - 635.67)
            C. Sensible Heat as a liquid 180 BTU`s, (32°to 212°), (635.67 - 815.67)
            D. Latent Heat of vapor is 970 BTU`s, (212°change in state), (815.67 - ~)
                *There is 673.67BTUs on 1 pound of water at 70°F
        3. Pounds per Squire Inch Absolute (Psi a) about 14.7 at sea level.
            A. 2.2 pound-mass of water fills a container whose volume is 4.2ft³
            B. 2.2 pound-mass of water has a volume of 15.12 Squire inches
            C. 2.2 pound-mass of water at 14.7 Psi a has 222.264 pounds of pressure on it.

4. Example Solution.

    A. Solve for 2.2pounds of 70°F water at 14.7psia.
       
        1. Pressure = 222.264 pounds of pressure
        2. Orbits per cycle = 3
            *(100% 666.801)(90% 600.1209)
        Heat Intensity = 1482.074 BTU`s

    B. Example 1, 2.2pounds of 70°F water at 14.7psia.
       
        1. Time Intensity
            222.267 X 3 / 1482.074 = 0.44991073320225575780966402487325
        2. Energy
            222.267 X 3 X 1482.074 = 988248.425274
   
    C. Example 2, Solve for 10% less Heat Intensity and pressure,
           
        1. Time Intensity
            2000.403 X 3 / 1333.8666 = 4.4991073320225575780966402487325
        2. Energy
            2000.403 X 3 X 1333.8666 = 8004812.2447194
   
    D. Compering the difference, 10% less Heat Intensity and pressure.
       
        1. Time Intensity    = 100%, with a  0% change.
        2. Energy        =  81%, with a 19% change.
           

Monday, April 2, 2012

Math to solve for Energy and Time, by Ezekial Davis

Math to solve for Energy and Time
by Ezekial Davis

Solve for Time: ( Heat Intensity / Pressure X Orbits per Cycle = Time Intensity)

Solve for Energy: (Heat Intensity ( Pressure X Orbits per Cycle) = Energy per Cycle)

note: when solving for Time Intensity under the same Electromagnetic field an equal drop in the percentage of heat and pressure will equal the same Time Intensity. It`s sometimes hard to understand how a slower and longer orbit can have the same time intensity. What you must understand is that the orbit does not change at all when changing heat and pressure equally, as a percent. changing one will change the other, its the EMF of the environment that effects the energy after the transfer of one took place. Think about this, I`m am sitting in my living room. It`s 90F, and the pressure is 14.7psi. i turn on my air conditioner and lowered the heat 5%. the pressure will also lower 5%. Once the rooms temp is stable at 5% less heat the Pressure will rise back to it`s 14.7psi, thus changing the time intensity and energy.
note: if heat and pressure keeps the same percentage loss then Energy will take a double loss**.
One thing I found when doing some fast math, other then this is a work in progress, is that at 70F and 14.7 psi a sustained loss of 10% heat and 10% pressure does not result in a 20% loss of energy, the energy lost is to the pen point at 19%. I hope to write more as I grow to understand this brake threw I made in my math.

Ezekial Davis