Math to solve for Energy and Time
by Ezekial Davis
by Ezekial Davis
Solve for Time: ( Heat Intensity / Pressure X Orbits per Cycle = Time Intensity)
Solve for Energy: (Heat Intensity ( Pressure X Orbits per Cycle) = Energy per Cycle)
note: when solving for Time Intensity under the same Electromagnetic field an equal drop in the percentage of heat and pressure will equal the same Time Intensity. It`s sometimes hard to understand how a slower and longer orbit can have the same time intensity. What you must understand is that the orbit does not change at all when changing heat and pressure equally, as a percent. changing one will change the other, its the EMF of the environment that effects the energy after the transfer of one took place. Think about this, I`m am sitting in my living room. It`s 90F, and the pressure is 14.7psi. i turn on my air conditioner and lowered the heat 5%. the pressure will also lower 5%. Once the rooms temp is stable at 5% less heat the Pressure will rise back to it`s 14.7psi, thus changing the time intensity and energy.
note: if heat and pressure keeps the same percentage loss then Energy will take a double loss**.
One thing I found when doing some fast math, other then this is a work in progress, is that at 70F and 14.7 psi a sustained loss of 10% heat and 10% pressure does not result in a 20% loss of energy, the energy lost is to the pen point at 19%. I hope to write more as I grow to understand this brake threw I made in my math.
Ezekial Davis
Solve for Energy: (Heat Intensity ( Pressure X Orbits per Cycle) = Energy per Cycle)
note: when solving for Time Intensity under the same Electromagnetic field an equal drop in the percentage of heat and pressure will equal the same Time Intensity. It`s sometimes hard to understand how a slower and longer orbit can have the same time intensity. What you must understand is that the orbit does not change at all when changing heat and pressure equally, as a percent. changing one will change the other, its the EMF of the environment that effects the energy after the transfer of one took place. Think about this, I`m am sitting in my living room. It`s 90F, and the pressure is 14.7psi. i turn on my air conditioner and lowered the heat 5%. the pressure will also lower 5%. Once the rooms temp is stable at 5% less heat the Pressure will rise back to it`s 14.7psi, thus changing the time intensity and energy.
note: if heat and pressure keeps the same percentage loss then Energy will take a double loss**.
One thing I found when doing some fast math, other then this is a work in progress, is that at 70F and 14.7 psi a sustained loss of 10% heat and 10% pressure does not result in a 20% loss of energy, the energy lost is to the pen point at 19%. I hope to write more as I grow to understand this brake threw I made in my math.
Ezekial Davis
